For Loop Hacker Rank Solution In C - Language | | Hacker Rank Solution
Question
A for loop is a programming language statement which allows code to be repeatedly executed.
- expression_1 is used for intializing variables which are generally used for controlling terminating flag for the loop.
- expression_2 is used to check for the terminating condition. If this evaluates to false, then the loop is terminated.
- expression_3 is generally used to update the flags/variables.
A sample loop will be
for(int i = 0; i < 10; i++) {
...
}
Input Format
You will be given two positive integers, and (), separated by a newline.
Output Format
For each integer in the interval :
- If , then print the English representation of it in lowercase. That is "one" for , "two" for , and so on.
- Else if and it is an even number, then print "even".
- Else if and it is an odd number, then print "odd".
For Loop Hacker Rank Solution In C - Language | | Hacker Rank Solution
Question
A for loop is a programming language statement which allows code to be repeatedly executed.
- expression_1 is used for intializing variables which are generally used for controlling terminating flag for the loop.
- expression_2 is used to check for the terminating condition. If this evaluates to false, then the loop is terminated.
- expression_3 is generally used to update the flags/variables.
A sample loop will be
for(int i = 0; i < 10; i++) {
...
}
Input Format
You will be given two positive integers, and (), separated by a newline.
Output Format
For each integer in the interval :
- If , then print the English representation of it in lowercase. That is "one" for , "two" for , and so on.
- Else if and it is an even number, then print "even".
- Else if and it is an odd number, then print "odd".
Answers
#include <stdio.h>
int main() {
int i,n1, n2;
const char* words[] = {"one", "two", "three","four","five","six","seven","eight","nine"};
scanf("%d", &n1);
scanf("%d", &n2);
for(i=n1;i<=n2;i++){
if((i <= 9)) {
printf("%s\n", words[i-1]);
}
else if((i > 9) && (i % 2 == 0)){
printf("even\n");
}
else {
printf("odd\n");
}
}
return 0;
}
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